2^2x^2+7x+5=1

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Solution for 2^2x^2+7x+5=1 equation: 



2^2x^2+7x+5=1

We move all terms to the left:

2^2x^2+7x+5-(1)=0

We add all the numbers together, and all the variables

7x+2^2x^2+4=0

We move all terms containing x to the left, all other terms to the right

7x+2^2x^2=-4

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